Feedback: Not quite! The vertex of the equation $y = 2(x + 3)^2 - 5$ is at (-3, -5). To find this, look at the equation: the term $(x + 3)$ inside the brackets is equivalent to $(x - (-3))$, so $h = -3$. The number outside the brackets, -5, represents $k$. Therefore, the vertex is at (-3, -5).
Feedback: Well done! The vertex of the equation $y = 2(x + 3)^2 - 5$ is at (-3, -5). To find this, look at the equation: the term $(x + 3)$ inside the brackets is equivalent to $(x - (-3))$, so $h = -3$. The number outside the brackets, -5, represents $k$. Therefore, the vertex is at (-3, -5).