Probability Tree Diagrams

Feedback: Not quite! The probability of drawing a red ball on the first draw is $\frac{6}{10}$ because there are 6 red balls out of a total of 10 balls. This can be simplified to $\frac{3}{5}$.

Feedback: Not quite! The probability of drawing a red ball on the first draw is $\frac{4}{10}$ because there are 4 blue balls out of a total of 10 balls. This can be simplified to $\frac{2}{5}$.

Feedback: Not quite! After drawing one blue ball, there are 3 blue balls left out of 9 total balls. Therefore, the probability of drawing another blue ball is $\frac{3}{9}$, which simplifies to $\frac{1}{3}$.

Feedback: Not quite! After drawing one blue ball, there are 3 blue balls, 6 red balls, and 9 total balls remaining. So, the probability of drawing a red ball now is $\frac{6}{9}$, which simplifies to $\frac{2}{3}$.

Feedback: Not quite! The probability of drawing a red ball first is $\frac{6}{10}$, and the probability of drawing a blue ball second is $\frac{4}{9}$. Multiply these probabilities to get $\frac{24}{90}$, which simplifies to $\frac{4}{15}$.

Feedback: Not quite! 1) Drawing a blue ball first, then a red ball: $\frac{4}{10} \times \frac{6}{9} = \frac{24}{90}$. 2) Drawing a red ball first, then a blue ball: $\frac{6}{10} \times \frac{4}{9} = \frac{24}{90}$. Adding these two probabilities gives a total of $\frac{48}{90}$, which simplifies to $\frac{8}{15}$.