Solving Equations with 2 Variables

Feedback: Not quite! The cost of $x$ snacks is $2x$, and the cost of $y$ waters is $y$. The total amount is $20, so the equation is $2x + y = 20$.

Feedback: Not quite! The cost of $x$ apples is $3x$, and the cost of $y$ oranges is $2y$. The total amount is $30, so the equation is $3x + 2y = 30$.

Feedback: Not quite! The equation formed here is: $2x + 3y = 40$, where $x$ is the number of pencils and $y$ is the number of erasers. Buying 5 pencils gives us $2(5) + 3y = 40$. Solving this, we find $y = 10$. So, you can still afford 10 erasers.

Feedback: Not quite! The equation formed here is: $2x + 3y = 40$, where $x$ is the number of pencils and $y$ is the number of erasers. Buying 8 erasers gives us $2x + 3(8) = 40$, which simplifies to $2x + 24 = 40$. Solving this, we find $x = 8 $. So, you can still afford 8 pencils.

Feedback: Not quite! The equation formed here is: $2x + 3y = 40$, where $x$ is the number of pencils and $y$ is the number of erasers. Buying 6 pencils and 3 erasers gives us $2(6) + 3(3) = 12 + 9 = 21$. So, you've spent $21. Subtracting this from your total, $40 - 21 = 19$, meaning you have £19 left.

Feedback: Not quite! The equation represented is 2x + 3y = 40, where x is the number of pencils and y is the number of erasers. Point P shows x = 5 and y = 10, meaning 5 pencils and 10 erasers can be purchased.