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Simultaneous Equations: Equal Values and Substitution Method

🎬 Video Tutorial

What is Equal Values Method? (0:01)

The Equal Values Method is a technique for solving systems of equations by isolating the same variable in both equations and setting them equal to each other.

  • Step 1: Express both equations in terms of y
    Rearrange each equation to solve for y:

$$
\begin{cases}
2x + y = 8 &\Rightarrow y = 8 – 2x \\
x – y = 1 &\Rightarrow y = x – 1
\end{cases}
$$

  • Step 2: Set the two new expressions equal
    Since both are equal to y, we set them equal to each other:

$$ 8 – 2x = x – 1 $$ $$ x = 3 $$

  • Step 3: Find y by substituting x
    Substituting $ x = 3 $ into any of the equations, preferably a simpler one, gives:

$$ y = 3 – 1 = 2 $$

  • Step 4: Verify the solution
    The final solution to the system of equations is:

$$ \{ x = 3, \quad y = 2 \} $$

What is Substitution Method? (1:25)

The Substitution Method is a technique for solving systems of equations by expressing one variable in terms of the other and substituting it into the second equation.

  • Step 1: Express one equation in terms of y
    Solve for $y$ in one equation:

$$
\begin{cases}
2x + y = 8 \\
x – y = 1 &\Rightarrow y = x – 1
\end{cases}
$$

  • Step 2: Substitute $y = x – 1$ into the other equation

$$2x + (x – 1) = 8 \Rightarrow x = 3$$

  • Step 3: Find $y$ by substituting $x$
    Substitute$x = 3$ back in $y = x – 1$ gives:

$$y = 3 – 1 = 2$$

  • Step 4: Verify the solution
    The final solution is:

$$ \{ x = 3, \quad y = 2 \} $$

Equal Values Method and Substitution Method (2:35)

Both methods always yield the same solution! However, one method may be simpler than the other, depending on the given equations.

Equal Values Method
This method is useful when isolating the same variable in both equations is easy.

🔹 Example:

$$
\begin{cases}
2x = 4y – 2 &\Rightarrow x = 2y – 1 \\
x – y = 2 &\Rightarrow x = y + 2
\end{cases}
$$

Since both are solved for \(x\), you can directly set them equal:

$$ 2y – 1 = y + 2 $$

This simplifies quickly to \( y = 3 \), making it an efficient method.

Substitution Method
This method is better when one equation is already solved for a variable or can be easily rearranged.

🔹Example:

$$
\begin{cases}
2x + 3y = 3 \\
3y = 2x – 1
\end{cases}
$$

Since the second equation is already solved for \(3y\), substituting it into the first equation:

$$ 2x + (2x – 1) = 3 $$

This quickly leads to \( x = 1 \).

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